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5x^2-115x+250=0
a = 5; b = -115; c = +250;
Δ = b2-4ac
Δ = -1152-4·5·250
Δ = 8225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8225}=\sqrt{25*329}=\sqrt{25}*\sqrt{329}=5\sqrt{329}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-115)-5\sqrt{329}}{2*5}=\frac{115-5\sqrt{329}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-115)+5\sqrt{329}}{2*5}=\frac{115+5\sqrt{329}}{10} $
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